I am repeating again, My question in the arrival section,is how to calculate pro

Question

I am repeating again, My question in the arrival section,is how to calculate probability that system is full?

Another question in the waiting line section how to calculate probability more than 3 customers waiting?

all the information is given in the Basic input section. I just want to know the customers who balk ( Arrival section), and probability more than 3 customers waiting (The waiting line)

Hle Home Insert Draw Page Layout Formulas Data ReviewV PROTECTED VIEW Office has detected a problem with this file. Editing it may harm your c SUBSCRIPTION EXPIRED On Wednesday, October 11, 2017, most features of Excel will be disable 014 Steady-State, Finite Capacity Queues Number of Servers, S 2 Queue Capacity, M5 Arrival Rate, - 60 Service Rate Capacity of each server, 25 Basic Inputs: Arrivals: Average Rate Joining System (Lambda-Bar) = 46.5623 Average Rate Leaving Without Service (balking)- 13.4377 Customers who Balk: Probability that System is Full (Pfull) 22.40% The Waiting Line: Average Number Waiting in Queue (Nq) 2.700 Average Waiting Time (Tq) 0.045 Q: Probability of more than| 3 |customers waiting -41.06% Service: Average Utilization of Servers 93.12% Average Number of Customers Being Served (Ns)- 1.86249 The Total System (waiting line plus customers being served): Average Number in the System (N) 4.563 Average Time in System (Tq+ Ts)- 0.09799 n = total number of customers in the system q Probability Distribution: number of customers in the waiting line n P(n) Cumulaive 0 00313 0.0313 1 0.0750 0.1063 2 0.0900 0.1963 3 0.1080 0.3043 4 0.1296 0.4339 5 0.1555 0.5894 6 0.1866 0.7760 7 0.2240 1.0000 q P(q) Cumuladive 0 0.1963 0.1963 1 0,1080 0.304 2 0.1296 0.4339 3 0.1555 0.5894 4 0.1866 0.7761 5 0.2240 1.0000

Explanation / Answer

See, look at the probabilities P(q) for customers waiting in queue.Now, your question regarding to customers(who balk) is simple.

How will you find that? Simply, the waiting line is full, that it is queue is having 5 members. So, simply look at p(q) for q=5, which is .2240

Your, next question -more than 3 customers waiting is simply the sum of P(q) for q=4 and 5, 4 customers and 5 customers in waiting line

Hence, answer is .1866 + .2240=.4106

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.