Acetic acid vs Taste: (e) You should detect one or more potential problems with
ID: 2923023 • Letter: A
Question
Acetic acid vs Taste:
(e) You should detect one or more potential problems with the model
through the work.
(f) Using the new model that was estimated for part (e), find the
95% confidence interval for mean taste when acetic acid has a
value of 4.5.
(g) Are there any other problems remaining with the model after
what was done in part (e)? Justify your answer. Note that you
do not need to actually implement any changes to the model.
Explanation / Answer
(e) You should detect one or more potential problems with the model through the work.
For the given two variables, it was observed that there is a considerable positive linear relationship exists between the two variables taste and acetic. We can find the regression equation for the dependent variable taste based on the independent variable acetic. We have to use regression model for given data. The regression output is given as below:
SUMMARY OUTPUT
Regression Statistics
Multiple R
0.549539299
R Square
0.301993441
Adjusted R Square
0.277064635
Standard Error
13.82123774
Observations
30
ANOVA
df
SS
MS
F
Significance F
Regression
1
2314.141512
2314.14151
12.11423623
0.001658192
Residual
28
5348.745155
191.026613
Total
29
7662.886667
Coefficients
Standard Error
t Stat
P-value
Lower 95%
Upper 95%
Intercept
-61.49861238
24.84637942
-2.4751539
0.019637301
-112.3941128
-10.60311199
Acetic
15.64776721
4.49577282
3.48055114
0.001658192
6.438594178
24.85694024
(f) Using the new model that was estimated for part (e), find the 95% confidence interval for mean taste when acetic acid has a value of 4.5.
Regression equation is given as below:
Taste = -61.4986 + 15.6478*Acetic
If acetic acid = 4.5
Taste = -61.4986 + 15.6478*4.5
Taste = 8.9165
Critical t = 3.48055114
SE = 4.49577282
Lower limit = 8.9165 - 3.48055114*4.49577282 = -6.731267214
Upper limit = 8.9165 + 3.48055114*4.49577282 = 24.56426721
Confidence interval = (-6.73, 24.56)
(g) Are there any other problems remaining with the model after what was done in part (e)? Justify your answer. Note that you do not need to actually implement any changes to the model.
No, there are no any problems remaining with the model. For the given overall model, it is observed that model is statistically significant as p-value is given as 0.00166. Also, both coefficients are statistically significant.
SUMMARY OUTPUT
Regression Statistics
Multiple R
0.549539299
R Square
0.301993441
Adjusted R Square
0.277064635
Standard Error
13.82123774
Observations
30
ANOVA
df
SS
MS
F
Significance F
Regression
1
2314.141512
2314.14151
12.11423623
0.001658192
Residual
28
5348.745155
191.026613
Total
29
7662.886667
Coefficients
Standard Error
t Stat
P-value
Lower 95%
Upper 95%
Intercept
-61.49861238
24.84637942
-2.4751539
0.019637301
-112.3941128
-10.60311199
Acetic
15.64776721
4.49577282
3.48055114
0.001658192
6.438594178
24.85694024
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