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Question

M Cory@ ×Vdc Secure I https://www.mathxl.com/Student/ ::: Apps For quick access, place your bookmarks here on the bookm @ Other bookma CRN 15780 Homework: Section 6.1 Homework Score: 0 of 1 rpt 6.1.46-T Save | 9 of 12 (8 complete) HW Score: 66.67 Question Help A random sample of the closing stock prices in dollars for a company in a recent year is listed below. Assume that is $1 89. Construct the 90% and 99% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals 16.59 22.69 18.58 16.82 20.75 17.14 19.11 20.92 18.68 16.87 18.68 15.34 19.75 16.41 18.93 18.46 The 90% confidence interval is Round to two decimal places as needed.) Enter your ansver ih the parts

Explanation / Answer

Standard deviation of sampling distribution, x = / sqrt( n ) = 1.89/sqrt(16) = 0.4725

sampling distribution mean, x = 295.72/16 = 18.4825

For 90% CI, zcrit = +/- 1.64

90% CI = x +/- zcrit * x = 18.4825 +/- 1.64 * 0.4725 = (17.7076, 19.2574)