5) Suppose that airplane de-icing equipment and compounds are being compared in
ID: 2922790 • Letter: 5
Question
5) Suppose that airplane de-icing equipment and compounds are being compared in a safety study. Specifically, two different manufacturers are being considered, A and B, and for each two different de-icing compounds are tested C1 and C2. De-icing of an airplane is considered non-effective if the airplane cannot take off without needing to be de-iced a second (or more) time, that is if the airplane ices up again while waiting for permission to takeoff. Suppose that the following results have been compiled; De-icing Compound Manufacturer Number Non-Effective 36 32 23 18 Number Effective 264 468 477 282 C2 C2 a) What is the probability that de-icing using manufacturer A's equipment will be effective? b) What is the probability that de-icing using manufacturer B's equipment will be non-effective? c) If the wings of an aircraft ice up prior to takeoff, what is the probability that compound C2 was used? d) Which compound is superior? e) Which manufacturer produces superior equipment?Explanation / Answer
Total effective for A = 264 +468 =
total number = 36+32 +264 +468 , so probabilityfor effective (264 +468)/ (36+32 +264 +468) = 0.915
For B , total non effective is (23+18)
Total number is (23+18+477+282) so probability is (23+18) / (23+18+477+282) = 0.0512
Total non effective for C1 is (36+23)
Total C1 are (36+23+264 +477) , so non effecitve proportion is (36+23) /(36+23+264 +477) *100 = 7.37%
for C2 it is (32+18)/(32+18+468+282) *100 = 6.25% , hence C2 is superior
For A
total number = 36+32 +264 +468 , so proportion for effective (264 +468)/ (36+32 +264 +468) = 0.915 = 91.5%
for B
(477+282)/(477+282+23+18 ) = 0.9485 = 94.85%
Hence B produces more effectives
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