A box of 10 gloves contains two left-handed gloves and eight right-handed gloves

Question

A box of 10 gloves contains two left-handed gloves and eight right-handed gloves. Complete parts (a) through (d) a. If two gloves are randomly selected from the box without replacement, what is the probability that both gloves selected will be right-handed? P(both right-handed).6222 (Round to four decimal places as needed.) b. If two gloves are randomly selected from the box without replacement, what is the probability there will be one right-handed glove and one left-handed glove selected? P(1 right-handed and 1 left-handed)(Round to four decimal places as needed.)

Explanation / Answer

P(Left handed glove) = n(left handed glove) / n(total glove)

= 2 / 10

p( right handed glove) = n (right handed glove) / n( total glove)

= 8 / 10

a)

p( both glove are right handed) = 8/10 * 7/9

= 0.6222

b)

p( one right handed and one left handed glove)

= P( first right handed and second left handed) + P(first left handed and second right handed)  

= 8/10 * 2 /9 + 2 / 10 * 8 /9

= 0.3556

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