5th. Problem 1 Find the values of x1-x8 reg lp 11 bdrms drive rec 471 107.45 0.0

Question

5th. Problem 1 Find the values of x1-x8 reg lp 11 bdrms drive rec 471 107.45 0.0000 0.4798 Adj R-squared = 0.4753 26941 Source df MS Number of obs = F (4, 466 Prob F x2 x3 Model31.1947391 Residual 33.8224355 466 .072580334 R-squared x1 Total 470.138334414 Root MSE 1p Coef. Std. Err.tP>ItI .0342369, 12.68 0.000 , .3669821 .5015377 1455622 .0170635 x5 0.000 1120311 1790932 x4 f 5, bdrms .1552753 .037876 4.10 0.000 x6 x7 rec.1664039 .0327296 5.08 0.000.10208812307197 6.247152 7.331913 cons 6.789533 .2760112 24.60 8 Problem 2 Consider the population regression model without an intercept

Explanation / Answer

x1 = total SS = SSmodel+SSresidual = 31.1947+33.8224 = 65.0171

x2 = total df - df of Residual
Therfore, x2 = 470-466 = 4

x3 = MSmodel = SSmodel/dfofModel =33.1947391/ 4 = 8.299

x4 = ?, x4/SE = 12.68, x4 = 12.68*SE = 12.68*.0342369 = .434

x5 = Coeffdbdrms/SE = .1455622/.0170635 = 8.35

x6 and x7 are lower and upper bounds of 95% Confinterval. So,
Coeff of Drive +/-Z*SE
= .1552753+/- 1.96*.037876
= .08 to .23
x6 = .08
x7 = .23

x8 = pvalue of _cons = 0.00
We have a t of 24.60 which is going to result at p-value of 0.00 for any df

Related Questions

Navigate

• Browse (All)
• Browse 5
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.