net/web/Student/ There are three nursing positions to be filled at Lilly Hospita

Question

net/web/Student/ There are three nursing positions to be filled at Lilly Hospital. There are 18 candidates qualified for alll three of the Position 1 is the day nursing supervisar; position 2 is the night nursing supervisor; and postion 3 is the nursing coordinator position is the positions. Determine the number of different ways the positions can be filled by these applicants. Need Help? ase The University of Montana ski team has thirteen entrants in a men's downhill ski event. The coach would like the fr the thirteen team entrants achieve first, second, and third places? st, second, and third places to go to the team members. In how many walys can Need Help? Head One professor grades homework by randomly choosing 7 out of 10 homework problems to grade. (a) How many different groups of 7 problerns can be chosen from the 10 preblems? groups (b) Probability extension: Jerry did only 7 problems of one assignment, what is the probability that the problems he did comprised the group that was selected to be graded? (Round your answer to four decimal places.) c) Savia did 9 problems. How many different groups of 7 did she complete? groups What is the probability that one of the groups of 7 she completed comprised the group selected to be graded? (Round your answer to four decimal places.) Need Help? Read

Explanation / Answer

Q 13

Since there are three job vacancies, the order of the choice matters.

Also, it does not matter who gets the job there will be one less person as the vacancy is closed

Hence, Permutations of 6 things taken 3 at a time:

6!/(6 - 3)! = 6! / 3! = 6*5*4 = 120 ways, so there are 120 ways a candidate can be selected.

Q14

Q 14

Since there are 3 places, the order of the choice matters.

Also, it does not matter who gets the job there will be one less person as the vacancy is closed

Hence, Permutations of 13 entrants taken 3 at a time:

13!/(13 - 3)! = 13! / 10! = 13*12*11 = 1716 ways, the position can be chosen

Q 15

a.

Answer to this is 10C7 = 10! / (7! x 3!) = 120 ways

b.

Since professor grades 7 out of 10 problems, Jerry has done 7 precisely and there are 120 ways professor can pick up 7 out of 10 problems, this means that there is only one chance for the professor to pick up 7 problems that Jerry did, mathematically the chances are 1 in 120 or 1/120 = 0.0083

c.

This is very similar to the a. here we have to calculate 9C7 = 9! / (7! x 1) = 36 ways

d.

Since there are 36 ways Silva’s 9 problems can be grouped and 120 ways jerry can pick 7 problems from 10, therefore probability that Silva’s 9 problems can be a part of the 7 that jerry picks is 36/120 = 0.300

As per rules, we are supposed to answer 1 question at a time. Since there were similar, I have answered all. Kindly post one question at a time. Good luck

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.