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https://www-awa.aleks.com/alekscgi//lslexe/1o u-IgNskr7j8P3H-BZFhlPLUg Q Search TRIGONOMETRIC FUNCTIONS Angular and linear speed Mercury has a diameter of 3032 miles. As the planet rotates on its axis, a point on its equator travels at 58,927 miles per year. (a) Find the angular speed of a point on its equator in radians per year. (b) Find the number of rotations the planet makes per year. Do not round any intermediate computations, and round your answer to the nearest whole number. (a) Angular speed: radians per year (b) Number of rotations per year: Check Explanation

Explanation / Answer

Given : Diameter of mercury = 3032 miles .    Radius of mercury ,r = 1516 miles .    Velocity of the point on equator ,v = 58927 miles per year .

(a) Angular Speed of the point on equator , w = ( v/r ) w = ( 58927 / 1516 ) w = 39

(b) No of rotations of planet , N = (30 * w) / ( pi ) N = 371   

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