ntr uy 1 points HPreCalc5 4.1.058. My Notes Ask Your Teache A rectangular garden

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ntr uy 1 points HPreCalc5 4.1.058. My Notes Ask Your Teache A rectangular garden next to a building is to be fenced on three sides. Fencing for the side parallel to the building costs $40 per foot, and material for the other two sides costs $80 per foot. If $1,500 is to be spent on fencing, what are the dimensions of the garden with the largest possible area? feet (parallel side) feet (other sides) Need Help? Talik to Tutor Additional Materials eBook 0/1 points | Previous Answers HPreCalc5 4.1.060. My Notes Ask Your Teacher A salesperson finds that her sales average 50 cases per store when she visits 10 stores a week. Each time she visits an store derreases hy 1 case. How many stores should she visit each week if

Explanation / Answer

1) Given that a rectangular garden is to be fenced on three sides, as on the fourth side, there is a building.

Cost for fencing on the parallel side to the building is $40 per foot and cost for the other two sides is $80 per foot.

Let, the length of that parallel side be x foot and length of the other two sides be y foot.

Then, by the given conditions, we get, (40*x) + 2*(80*y) = 1500

i.e., (40*x) + (160*y) = 1500

i.e., 2x + 8y = 75

The number of solutions of this equation is more than one.

But, we have to take that solution for which the area of that garden is largest.

Therefore, the solution is, x = 35/2 and y = 5.

Hence, the dimensions of the garden are 35/2 foot and 5 foot and the area is 175/2 square foot.

2) Second question is incomplete.

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