It has been reported that employment interviewers spend moretime talking to appl

Question

It has been reported that employment interviewers spend moretime talking to applicants who are hired than to applicants who arerejected. To determine wheter this is true for college studentsseeking summer employment through a university placement center, anexperimenter posing as an applicant accompanied a random sample ofreferees to their job interviews. A record of the duraion(inminutes) and out come of N-49 interviews was kept. the dataare Hired Rejected 30 23 19 17 21 24 18 18 24 26 22 19 25 27 13 22 29 24 15 15 24 22 18 19 23 25 17 17 24 26 20 20 28 23 18 18 25 24 19 17 24 27 23 19 26 12 25 25 18
Calculate, separately, the z-core for a value of 19 in the"Hired"condition, and then for value of 19 in the "Rejected" condition.How do the z-scores compare? Interpret the z-scores. It has been reported that employment interviewers spend moretime talking to applicants who are hired than to applicants who arerejected. To determine wheter this is true for college studentsseeking summer employment through a university placement center, anexperimenter posing as an applicant accompanied a random sample ofreferees to their job interviews. A record of the duraion(inminutes) and out come of N-49 interviews was kept. the dataare Hired Rejected 30 23 19 17 21 24 18 18 24 26 22 19 25 27 13 22 29 24 15 15 24 22 18 19 23 25 17 17 24 26 20 20 28 23 18 18 25 24 19 17 24 27 23 19 26 12 25 25 18 Hired Rejected 30 23 19 17 21 24 18 18 24 26 22 19 25 27 13 22 29 24 15 15 24 22 18 19 23 25 17 17 24 26 20 20 28 23 18 18 25 24 19 17 24 27 23 19 26 12 25 25 18 Hired Rejected 30 23 19 17 21 24 18 18 24 26 22 19 25 27 13 22 29 24 15 15 24 22 18 19 23 25 17 17 24 26 20 20 28 23 18 18 25 24 19 17 24 27 23 19 26 12 25 25 18

Explanation / Answer

Here, for the Hired the mean and standard deviation is givenby, =24.73077, =2.3589. Z=x-/ =19-24.73077/2.3589 =-2.43. Here, for the rejected the mean and standard deviation isgiven by, =18, =2.6285. Z=x-/ =19-18/2.6285 =0.38. A zcore can be compared to know how many standard deviationsthe original observation falls away from the mean, and in whichdirection. Observations larger than the mean are positive whenstandardized, and observations smaller than the mean arenegative. We can observe this in the case of the above problem. From the above z scores, we can say that the time taken toreject the college students is more than the time takento hire tha college students. Here, for the rejected the mean and standard deviation isgiven by, =18, =2.6285. Z=x-/ =19-18/2.6285 =0.38. A zcore can be compared to know how many standard deviationsthe original observation falls away from the mean, and in whichdirection. Observations larger than the mean are positive whenstandardized, and observations smaller than the mean arenegative. We can observe this in the case of the above problem. From the above z scores, we can say that the time taken toreject the college students is more than the time takento hire tha college students.

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