Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Hello, first time poster here, need some help with this homeworkquestion please!

ID: 2918531 • Letter: H

Question

Hello, first time poster here, need some help with this homeworkquestion please!


Suppose that after computing xn(dash on the x, don't know how todo the syntax) based on n sample observations x1,...,xn,another observation xn+1 becomes available. (i) What is the relationship between the mean of the first nobservations, the new observation, and the mean of all n+1observations? (ii) For the strength observations givenbelow:

22.2    40.4   16.4    73.7   36.6    109.9    30.0  4.4        33.1  66.7   81.5,

Explanation / Answer

< Xn>= average of n observations = sum of nobservations/n

ð Sum of n observations = <xn> * n

ð Sum of n+1 observations = sum of n observations +Xn+1

ð sum of n+1 observations = <xn> * n+Xn+1

ð Average of n+1 observations = (<xn> * n+Xn+1)/(n+1)

ð <Xn+1> = (<xn> * n+Xn+1)/(n+1)

Using the same formula

Average of 11 observations = (43.34*10 +81.5)/11 =46.80909

Hope this helps you. Keep posting for any help.

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Chat Now And Get Quote