The table below shows the data obtained from solids analysis of a water sample E
ID: 291810 • Letter: T
Question
The table below shows the data obtained from solids analysis of a water sample Express all answers in mg/L Express all answers in mg/L a. Calculate TS, TFS, TVS, TSS, FSS, and VSS using these data b. Using your results from part a, calculate TDS, FDS, and VDS Total solids data mass in g: volume in mL mass empty dish mass dish + dry solids mass dish + ignited solids volume wastewater tested Suspended solids data mass in g: volume in mL mass crucible + lass fiber filter mass crucible + glass fiber filter + dry solids mass crucible + glass fiber filter + ignited solids volume wastewater tested 66.7890 45.6873 66.8745 45.7111 66.8266 45.7007 100.0 250.0Explanation / Answer
Total solids : All the solids present in the water sample
Total solids = (((Mass of empty dish+dry solids) - Mass of empty of empty dish )* 1000)/ Vol of sample in ml
= (66.8745-66.789) *1000 / 100
= 0.85 g/L
= 85 mg/L
Total Fixed solids = Includes the solids that remain after igniting the total solids at 550 degree C in a muffle furnace.
Total Fixed solids = (mass of dish + ignited solids - mass of dish) * 1000/ sample in ml
= 66.8266 - 66.789 = 0.0376 * 10 = 0.376
= 0.376*100 = 37.6 mg/L
Total volatile solids = The difference between total solids and total fixed solids
= 85-37.6 = 47.4 mg/L
Total suspended solids = (((Mass of crucible + glass fiber filter + dry solids) - Mass of crucible + glass fiber filter )* 1000)/ Vol of sample in ml
=45.7111-45.6873 =0.0283 * 1000/250
=0.1132 g/L = 11.32 mg/L
Suspended fixed solids = Includes the solids that remain after igniting the suspended solids at 550 degree C in a muffle furnace.
Suspended fixed solids = (mass of crucible + glass fiber filter+ ignited solids - mass of crucible - glass filter) *1000 / sample volume in ml
= 45.7007-45.6873 = 0.0134 * 1000 /250
= 0.0536 * 100 = 5.36mg/L
Volatile suspended solids = Difference between total suspended solids and suspended fixed solids
= 11.32- 5.36 = 5.96 mg/L
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