1. A rearcher wanted to determine if the average sizesize of farms in two counti
ID: 2917789 • Letter: 1
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1. A rearcher wanted to determine if the average sizesize of farms in two counties in Pennsylvania were different. Hesamples 8 farms n Indiana county and dtermines the average size ofa farm is 191 acres with a standard deviation of 38 acres. He thansamples 10 farms in Green County and determines the average size ofa farm is 199 acres with a standard deviation of 12 cacres. Ahypothesis test was conducted at the 5% level of signifance. A. Ho: = 0 Ha: #0 B. Ho: H1 = 2 Ha: 1>2 C. Ho: 1=2 Ha: 1>2 D. Ho:1=2 Ha:1=2 E. Ho:o=0 Ha:0o<0 2. A reasearcher wanted to determine if the average size offarms in two counties in Pennsylvania were different. Hesamples 8 famrs in Indiana county and determines the average sizeof a farmis 191 acres with a standard deviation of 38 acres. Hethen samples 10 farms in Green County and determine the averagesize of a farm is 199 acres with a standard deviation of 12acres. A hypothesis test was conducted at the 5% level ofsifnificance. A. 0.22 B. 1.57 C. 1.85 D. - 1.85 E.-0.57 1. A rearcher wanted to determine if the average sizesize of farms in two counties in Pennsylvania were different. Hesamples 8 farms n Indiana county and dtermines the average size ofa farm is 191 acres with a standard deviation of 38 acres. He thansamples 10 farms in Green County and determines the average size ofa farm is 199 acres with a standard deviation of 12 cacres. Ahypothesis test was conducted at the 5% level of signifance. A. Ho: = 0 Ha: #0 B. Ho: H1 = 2 Ha: 1>2 C. Ho: 1=2 Ha: 1>2 D. Ho:1=2 Ha:1=2 E. Ho:o=0 Ha:0o<0 2. A reasearcher wanted to determine if the average size offarms in two counties in Pennsylvania were different. Hesamples 8 famrs in Indiana county and determines the average sizeof a farmis 191 acres with a standard deviation of 38 acres. Hethen samples 10 farms in Green County and determine the averagesize of a farm is 199 acres with a standard deviation of 12acres. A hypothesis test was conducted at the 5% level ofsifnificance. A. 0.22 B. 1.57 C. 1.85 D. - 1.85 E.-0.57Explanation / Answer
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