Hi i was wondering if you tell me is the followingcorrect: What i have is: popul

Question

Hi i was wondering if you tell me is the followingcorrect: What i have is: population is normal. sample size n = 20 sample mean = x-bar = 80.2 sample s.d. = 4 question is to find the confidence interval for the 90thpercentile of the population +z.9, given =3? what i have is the following: 90% c.i. - t 0.1/2, 19 = 1.729 90% c.i. for true population mean is calculated using thefollowing formula: -> ( 80.2 -1.729 * 3/20, 80.2 + 1.729 *3/20) = (80.2 - 1.729 * 0.67082, 80.2 + 1.729 * 0.67082) = (79.04015222, 81.35984778) is the formula correctfor this?

Explanation / Answer

( 80.2 -1.729 * 3/20, 80.2 + 1.729 * 3/20) as   I read your formula is replaplaced by 4 (80.2-1.729*0.894427, 80.2+1.729*0.894427) ( 78.65353       , 81.7464646)

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.