In the lecture we discussed that: S^(e) = S^2 Y * (1 - r^2) We want to predict t

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Question

In the lecture we discussed that:

S^(e) = S^2 Y * (1 - r^2)

We want to predict test anxiety from general level of anxiety andwe find r = + 0.4. We collect this data on a random sample of 100students. What is the best answer?

Choose one answer. A. S^2 (Y) is thevariance of the scores on general anxiety and S^2( e) is thevariance of the residulas or error. B. Given themagnitude of correlation, 60% of the variance in test anxietycannot be predicted from general anxiety. C. S^2 (Y) is thevariance of the scores on test anxiety and S^2( e) is the varianceof the residulas or error. D. If thecorrelation between test anxiety and general anxiety was equal to-1, then the variance of the residuals or the error of predictionwould be 100%. In the lecture we discussed that:

S^(e) = S^2 Y * (1 - r^2)

We want to predict test anxiety from general level of anxiety andwe find r = + 0.4. We collect this data on a random sample of 100students. What is the best answer?

Choose one answer. A. S^2 (Y) is thevariance of the scores on general anxiety and S^2( e) is thevariance of the residulas or error. B. Given themagnitude of correlation, 60% of the variance in test anxietycannot be predicted from general anxiety. C. S^2 (Y) is thevariance of the scores on test anxiety and S^2( e) is the varianceof the residulas or error. D. If thecorrelation between test anxiety and general anxiety was equal to-1, then the variance of the residuals or the error of predictionwould be 100%. Choose one answer. A. S^2 (Y) is thevariance of the scores on general anxiety and S^2( e) is thevariance of the residulas or error. B. Given themagnitude of correlation, 60% of the variance in test anxietycannot be predicted from general anxiety. C. S^2 (Y) is thevariance of the scores on test anxiety and S^2( e) is the varianceof the residulas or error. D. If thecorrelation between test anxiety and general anxiety was equal to-1, then the variance of the residuals or the error of predictionwould be 100%.

Explanation / Answer

C.S2Y is the variance of the scores on testanxiety and S2e is the variance of theresidulas or error.

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In the lecture we discussed that: S^(e) = S^2 Y * (1 - r^2) We want to predict t

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In the lecture we discussed that: S^(e) = S^2 Y * (1 - r^2) We want to predict t

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