1. Use a P-value to conduct a hypothesis test In 1990, 58% of Americans 18 youar
ID: 2915414 • Letter: 1
Question
1. Use a P-value to conduct a hypothesis testIn 1990, 58% of Americans 18 youars or older reported they have agreat deal of concern regarding air pollution. On 20 February2001, the Gallup Organization released results of a poll in whcih592 of 1004 Americans 18 years old or older stated that they have agreat deal of concern regarding the level of air pollution inAmerica. is there evidence at the 5% level of significance toconclude that the proportion of Americans have a great deal ofconcern about the level of air pollution in America wassignificantly different in 2001 than in 1990? need to see how you got answer 1. Use a P-value to conduct a hypothesis test
In 1990, 58% of Americans 18 youars or older reported they have agreat deal of concern regarding air pollution. On 20 February2001, the Gallup Organization released results of a poll in whcih592 of 1004 Americans 18 years old or older stated that they have agreat deal of concern regarding the level of air pollution inAmerica. is there evidence at the 5% level of significance toconclude that the proportion of Americans have a great deal ofconcern about the level of air pollution in America wassignificantly different in 2001 than in 1990? need to see how you got answer need to see how you got answer
Explanation / Answer
Ha: P not = .58
Z = (phat - P)/SE
phat = 592/1004=.5896 P=.58 Q=1-P=.42 n=1004 SE= square root of (P xQ divided by n ) = .01558 Z= .62
P(z>.62) = 1 - .7324= .2676 but since its 2 sided you divide it by two. So,= .1338
P value is greater then yoursignificance value (.05) So Ho is not rejected, test isinsignificant, there is no difference between the the twoyears.
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