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Let A be the event that randomly choosen American is Hispanic, andlet B be the e

ID: 2914313 • Letter: L

Question

Let A be the event that randomly choosen American is Hispanic, andlet B be the event that the person is white.
                               Hispanic              Not Hispanic
               asian      0.000                       0.036
              black       0.003                     0.121
              white      0.060                       0.691
             others       0.062                     0.027

d) Express "the person chosen is a nonhispanic white" in terms ofevents A and B. what is the probability of this event?

My question:
I still don't understand how Ihave to solve this problem. I tried the following:

P(A)= 0,875
P(B)= 0,751

P(A and B)= P(A) x P(B), so 0,875 x 0,751= 0,657

But you can't use this rule, because here P(A) and P(B) aredependent. But at school they say it was the correct answer. Idon't understand why.

Let A be the event that randomly choosen American is Hispanic, andlet B be the event that the person is white. Let A be the event that randomly choosen American is Hispanic, andlet B be the event that the person is white.
                               Hispanic              Not Hispanic
               asian      0.000                       0.036
              black       0.003                     0.121
              white      0.060                       0.691
             others       0.062                     0.027

d) Express "the person chosen is a nonhispanic white" in terms ofevents A and B. what is the probability of this event?

My question:
I still don't understand how Ihave to solve this problem. I tried the following:

P(A)= 0,875
P(B)= 0,751

P(A and B)= P(A) x P(B), so 0,875 x 0,751= 0,657

But you can't use this rule, because here P(A) and P(B) aredependent. But at school they say it was the correct answer. Idon't understand why.

Explanation / Answer

The person chosen is a nonhispanic white" in terms of events Aand B That is non-Hispanic is Ac (A compliment) and B(white) ==>P(Ac and B) = P(B) P( Ac|B) So P(A) = 0.125 and P(B) = 0.751 Now P(Ac ) = 1- P(A) = 1-0.125 = 0.875 Required probability = 0.875 *(0.691/0.875)= 0.691 What you did is correct. What you did is correct.
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