6) For three trials,find the probability that the number of red balls selected i

Question

6) For three trials,find the probability that the number of red balls selected is notgreater than two 6) P(not greater than two) = 1 - P(greater than two) = 1 - P(3red balls) = 1 - (4/6)(4/6)(4/6) = 19/27 Prove: if each of two events A and B, has a positiveprobability, and if A and B are independent events, then they arenot disjoint. (Do not confuse independence with disjoint) Since P(A) x P(B) isindependent
P(A) x P(B) = P(A and B)
Since A and B has positive probability, P(A and B) cannot bezero.
Since P(A and B) is not zero, Events A and events B haveintersect.
Thus, they are not disjoint Are these answers correct? 6) For three trials,find the probability that the number of red balls selected is notgreater than two 6) P(not greater than two) = 1 - P(greater than two) = 1 - P(3red balls) = 1 - (4/6)(4/6)(4/6) = 19/27 Prove: if each of two events A and B, has a positiveprobability, and if A and B are independent events, then they arenot disjoint. (Do not confuse independence with disjoint) Since P(A) x P(B) isindependent
P(A) x P(B) = P(A and B)
Since A and B has positive probability, P(A and B) cannot bezero.
Since P(A and B) is not zero, Events A and events B haveintersect.
Thus, they are not disjoint Are these answers correct? 6) P(not greater than two) = 1 - P(greater than two) = 1 - P(3red balls) = 1 - (4/6)(4/6)(4/6) = 19/27 Prove: if each of two events A and B, has a positiveprobability, and if A and B are independent events, then they arenot disjoint. (Do not confuse independence with disjoint) Since P(A) x P(B) isindependent
P(A) x P(B) = P(A and B)
Since A and B has positive probability, P(A and B) cannot bezero.
Since P(A and B) is not zero, Events A and events B haveintersect.
Thus, they are not disjoint Are these answers correct?

Explanation / Answer

If X can take values of 0, 1, 2 or 3, then
P(X = not greater than two) = P(X = 0,1,2) = 1 - P(X= 0,1,2) = 1 -P(X = 3)

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