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A special cable has a breaking strength of 700 pounds. The standarddeviation of

ID: 2913460 • Letter: A

Question

A special cable has a breaking strength of 700 pounds. The standarddeviation of the population is 16 pounds. A researcher selects asample of 34 cables and finds that the average breaking strength is696 pounds. Can one reject the claim that the breaking strength is700 pounds? Find the P- value. Should the null hypothesis berejected at = 0.01? Assume that the variable is normallydistributed. Round all intermediate calculations to four decimalplaces.



A. There is not enough evidence to reject the nullhypthosis that the breaking strength is 700 pounds.


B. There is enough evidence to reject the nullhypthosis that the breaking strength is 700 pounds

Explanation / Answer

A specialcable has a breaking strength of 700 pounds. The standard deviationof the population is 16 pounds. A researcher selects a sample of 34cables and finds that the average breaking strength is 696 pounds.Can one reject the claim that the breaking strength is 700 pounds?Find the P- value. Should the null hypothesis be rejected at = 0.01? Assume that the variable is normally distributed.Round all intermediate calculations to four decimalplaces. (A) There is not enough evidence to reject thenull hypthosis that the breaking strength is 700pounds. B. There is enough evidence to reject the nullhypthosis that the breaking strength is 700 pounds EXPLANATION: {Null Hypothesis} = {H0: Mean Breaking StrengthEquals 700} {Alternate Hypothesis} = {Ha: Mean BreakingStrength NOT Equal To 700} {Population Mean} = 700 {Population Standard Deviation} = 16 {Sample Size} = 34 {Sample Mean} = 696 {Std Error Of Mean} = (16)/Sqrt[ 34 ] = 2.744 {Z Value For (696)} = ((696) - (700))/(2.744) = -1.458 {P-Value For (696)} = 1.0 - Prob{-1.458 {Do NOT Reject Null Hypothesis @0.01} .
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