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A 0.010.01 significance level is used for a hypothesis test of the claim that wh

ID: 2909972 • Letter: A

Question

A

0.010.01

significance level is used for a hypothesis test of the claim that when parents use a particular method of gender? selection, the proportion of baby girls is

greatergreater

than 0.5. Assume that sample data consists of

5555

girls in

100100

?births, so the sample statistic of

StartFraction 11 Over 20 EndFraction1120

results in a z score that is 1 standard deviation

aboveabove

0. Complete parts? (a) through? (h) below.Click here to view page 1 of the Normal table.

LOADING...

Click here to view page 2 of the Normal table.

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a. Identify the null hypothesis and the alternative hypothesis. Choose the correct answer below.

A.

Upper H 0H0?:

pequals=0.5

Upper H 1H1?:

pgreater than>0.5

B.

Upper H 0H0?:

pequals=0.5

Upper H 1H1?:

pless than<0.5

C.

Upper H 0H0?:

pequals=0.5

Upper H 1H1?:

pnot equals?0.5

D.

Upper H 0H0?:

pnot equals?0.5

Upper H 1H1?:

pgreater than>0.5

b. What is the value of

alpha???

alpha?equals=nothing

?(Type an integer or a? decimal.)

c. What is the sampling distribution of the sample? statistic?

chi squared?2

Normal distribution

Student? (t) distribution

d. Is the test? two-tailed, left-tailed, or? right-tailed?

RightRight?-tailed

LeftLeft?-tailed

?Two-tailed

e. What is the value of the test? statistic?

The test statistic is

nothing.

?(Type an integer or a? decimal.)

f. What is the? P-value?

The? P-value is

nothing.

?(Round to four decimal places as? needed.)

g. What are the critical? value(s)?

The critical? value(s) is/are

nothing.

?(Round to two decimal places as needed. Use a comma to separate answers as?needed.)

h. What is the area of the critical? region?

The area is

nothing.

?(Round to two decimal places as? needed.)

Click to select your answer(s

Explanation / Answer

a) Option-A) H0 : P = 0.5

Ha : P > 0.5

b) Alpha = 0.01

c) Normal distribution

d) Right - tailed

e) The test statistic z = (p - P)/Sqrt(P(1 - P)/n)

= (0.55 - 0.5)/Sqrt(0.5 * 0.5/100)

= 1

f) P-value = P(Z > 1)

= 1 - P(Z < 1)

= 1 - 0.8413

= 0.1587

g) At alpha = 0.01, the critical value is z* = 2.33

h) Area of the critical region = 0.99