Quiz: Chapter 5 Review Quiz Submit Quiz This Question: 1 pt 4 of 19 (1 complete)

Question

Quiz: Chapter 5 Review Quiz Submit Quiz This Question: 1 pt 4 of 19 (1 complete)I This Quiz: 19 pts possibk Use the standard normal table to tind the z-score that corresponds to the given percentil If the area is not in the table,use the entry dosest to the area If the area is haltway betveen two entries, use the z-score hailway belween thepdng z-scores. If convenient, use technology to find the z-score P2 ack to new page 1 9f the table Click to wew page 2 of the table The z-score that corresponds to P2 is ? Round to two decimal places as needed)

Explanation / Answer

Q-4

P2= 0.02

you look for the area to the left of the z-score from the table.

i found a z-score of -2.06 yielded .0197 area to the left of that z-score and i found a z-score of -2.05 yielded .0202 area to the left of that z-score.

.0202 is closer to .02 than .0197, so the z-score chosen as the solution is a z-score of -2.05.

the z-score of -2.05 is an addition of -2.0 in row 17with .05 in column 6

it's the intersection of the area in the row of -2.0 with the column of .05.

So Ans is Z=-2.05

14.

mean = 1483
standard deviation = 310
z-score = (data - mean) / standard deviation
z-score-1 = (1900 - 1483) / 310 = 1.3452
z-score-2 = (1250 - 1483) / 310 = -0.7516

z-score-3 = (2180 - 1483) / 310 = 2.2484

z-score-4 = (1380 - 1483) / 310 = -0.3324

As a general rule, z-scores lower than -1.96 or higher than 1.96 are considered unusual and interesting. That is, they are statistically significant outliers.

So value 2180 is unusual

look in the z-score table to find a z-score
the percentage of students who score below 1900 is equal to the area to the left of the z-score which is equal to .9107 * 100% = 91.07%
the percentage of students who score above 1250 is equal to the area to the right of the z-score which is equal to 0.2261 * 100% = 22.61%

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