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A company took a random sample of a batch of its deluxe mixed nuts and found 65

ID: 2909487 • Letter: A

Question

A company took a random sample of a batch of its deluxe mixed nuts and found 65 cashew, 30 almond, 25 macadamia and 20 brazil. The company want to test the claim that the frequency distribution of types of nuts are equally likely for a batch of mixed nuts using a significance level of 0.05. Answer questions 5-7:

1. State the null and alternative hypotheses:

Question 5 options:

a)

H0: the four types of nuts have the same frequencies

H1: Cashew and Brazil nuts have different counts.

b)

H0:At least one type of nut has a different frequency count from the other nuts

Ha: The four types of nuts have the same frequencies

c)

H0: The four types of nuts have the same frequencies

Ha: The four types of nuts all have different frequencies.

d)

H0: The four types of nuts have the same frequency counts

Ha: At least one type of nut has a different frequency than the other three.

2. What is the test statistic? (choose the closest one)

Question 6 options:

a)

128.4

b)

66

c)

35.7

d)

140

What is the p-value?

a)

0.0306

b)

0.0860

c)

0.0000

d)

0.0576

a)

H0: the four types of nuts have the same frequencies

H1: Cashew and Brazil nuts have different counts.

b)

H0:At least one type of nut has a different frequency count from the other nuts

Ha: The four types of nuts have the same frequencies

c)

H0: The four types of nuts have the same frequencies

Ha: The four types of nuts all have different frequencies.

d)

H0: The four types of nuts have the same frequency counts

Ha: At least one type of nut has a different frequency than the other three.

2. What is the test statistic? (choose the closest one)

Question 6 options:

a)

128.4

b)

66

c)

35.7

d)

140

What is the p-value?

a)

0.0306

b)

0.0860

c)

0.0000

d)

0.0576

Explanation / Answer

5)
option D) is correct

6)

TS = 35.7

d) 35.7 is correct

p-value = 8.60575E-08

C) is correct

p Oi Ei (Oi-Ei)^2/Ei 0.25 65 35 25.71428571 0.25 30 35 0.714285714 0.25 25 35 2.857142857 0.25 20 35 6.428571429 1 140 140 35.71428571 TS 35.71428571 critical value 7.814727903 p-value 8.60575E-08
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