A poll 4.8 Twitter users and news, Part I: estimate was 2.4%, and a normal distr

Question

A poll 4.8 Twitter users and news, Part I: estimate was 2.4%, and a normal distribution may be used to model the sample proportion construct a 99% confidence interval for the fraction of U.S. adult Twitter users who get some news on Twitter, and interpret the confidence interval in context (please round all percentages to 2 decimal places) in 2013 found that 52% of US adult Twitter users get at least some news on Twitter (Pew, 2013). The standard error for this Interpret the meaning of your confidence interval: we are 99% confident that the true proportion of US adult twitter users who get "There is a 99% probability that the proportion of US adult twitter users who get some news on Twitter is within our confidence interval some news on Twitter is within our confidence interval 99% of confidence intervals will be contain the correct sample proportion of U.S. adult twitter users who get some news on Twitter Points possible: 1 This is atmempt 1 of 2 4 8 5 0

Explanation / Answer

Ans:

For 99% confidence interval,z=2.576

standard error=0.024

Margin of error=2.576*0.024=0.0618

99% confidence interval for proportion

=0.52+/-0.0618

=(0.4582, 0.5818)

or (45.82% , 58.18%)

First option is correct(We are 99% confident that the true proportion of U.S. adult twitter users.....)

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