Question 3 0/1 pts It is desired to compare the average amount of time students

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Question 3 0/1 pts It is desired to compare the average amount of time students with a tattoo and students without a tattoo exercise per week. Random and independent samples were selected and the data was analyzed in the Statistix software and the following printout was generated Two-Sample T Tests for Exercise by Tattoo Tattoo N Mean SDSE 60 7.1167 47160 0.6088 22 6.6364 3.5395 0.7546 No Yes Difference 0.4803 4.4374 1.1060 T-Tests for Mean Difference Null Hypothesis: difference Alternative Hyp: difference Lower Upper Method Variances DF T P 95% CI, 95% CI, Pooled Satterthwaite Unequal 49.7 0.50 0.6225 -1.4675 2.4281 Homogeneity of Variances DFFP Folded F Test Equal 80 0.43 0.6653-1.7207 2.6813 59.21 1.78 0.0731 If you were conducting a test of hypothesis to determine if there is a difference in the mean exercise times of all tattooed and non- tattooed students, which p-value would you interpret? ??

Explanation / Answer

Ans:

Test statistic;

t=0.43

df=80

p-value=tdist(0.43,80,2)=0.6653

Correct option will be 0.6653

(We will consider the case of equal variances,as from homogenity of variances test results,p-value=0.0731,which is greater than 0,so population variances are equal.)

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