MAT 152-03 IN Statistical Methods I (Summer 2018 Test: MAT 152 FINAL EXAM (30 qu

Question

MAT 152-03 IN Statistical Methods I (Summer 2018 Test: MAT 152 FINAL EXAM (30 questions, 210 minutes) This Question: 1 pt Matt DeSutter& 7/30/18 12 Time Remaining: 03 29-24 Sub This Test: 30 pts 3 of 30 (0 complete) Temperature(F) Frequana Use the given freqaancy distrbution to Snd the a) class width. b) dless midpoints c) dlass boundaries 35.37 38.40 44.46 47.49 53-55 a) What is the class width Tyge an integer or a decima ) Wha are the dass midpoints? Complete the luble below (Tye ineges or decimals TemperstureF)Frequeney 4 37 38 40 1.43 44 40 47.49 50-52 355 ) What are the class toundaries7 Complete the table below (Type ingers or decimas Temperature ) Frequency Class boundaries 840 44 40 47-40 Enter your answer in each of the anewer boxes

Explanation / Answer

a)

class width is the difference between the upper and lower class boundaries of any class.

therefore class width = 37-35 = 2

b)

midpoits are calculated by

Class midpoint is found by adding the upper and lower class boundaries of any class and dividing the results by 2

c)

Class Boundaries are the midpoints between the upper class limit of a class and the lower class limit of the next class in the sequence. It is 0.5 more or less of a class limit. Therefore, each class has an upper and lower class boundary.

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Thanks

Class Frequency Lower Limit Upper Limit Midpoints 35-37 1 35 37 36 38-40 3 38 40 39 41-43 5 41 43 42 44-46 11 44 46 45 47-49 7 47 49 48 50-52 7 50 52 51 53-55 1 53 55 54

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