MINDTAP Search this course Yuylu Ch. 9 HW Check My Work (2 remaining) eBook Vide
ID: 2908613 • Letter: M
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MINDTAP Search this course Yuylu Ch. 9 HW Check My Work (2 remaining) eBook Video Individuals filing federal income tax returns prior to March 31 received an average refund or $1,080. Consider the population or·last-minute" filers who mail?eir tax return during the last five days of the income tax period (ypically April 10 to Apri 15) a. A researcher suggests thet a reason individuals wait until the last five days is that on average these individuals receive lower refunds than do early filers. Develop apprapriate hypotheses such that rajection of Ho will support the researcher's contention. 10, : ? is [ Select your answer Hai ? is-select your answer 12. b. For a sample of 400 individuels who filed a tax retum between April 10 and 15, the sample mean refund was 5910. Based on prior experience a population standard deviation of ?-$1,000 may be assumed. what is the p-value {to 4 decimals)? 13. c. Using ?-0.05, can you conclude that the population mean refund for·last minute. nlers is less than the population mean refund for early filers? Seleet your answer Answer the next three questions using the oritical value approach. d. Using ?-0.05, what is the critical value for the test statistic? Enter negative value as negative number state the rejection rule: Reject cx-0. D5 if z is l -select your answer- the critical value. Using ?-0.05, can you condude that the population mean refund for-last minute.. nlers is less than the population mean refund for early niers? Select your answer Check My Work (2 remaining) appropriate hypotheses such that rejection of Ho will support the researcher's contention. o sSelect your answer : is Select your answer b. For a sample of 400 individuals who filled a tax returm between April 10 and 15, the sample mean refund was $910. Based an prior experience a papulation standard deviation of ?-$1,600 may be assumed. what is the p-value (to 4 decimals)? 12. 13. c. Using ? = 0.05, can you conclude that the population mean refund for·last minute. filers is less than the population mean refund for early filers? Select your answer- Answer the next three questions using the criticel value approach. d. Using ?-0.05, what is the critical value for the test statistic? Enter negative value as negative number State the rejection rule: Reject ?-0. 05 if z is l-select your answer- : |the critical value. Using ?-0.05, can you condude that the population mean refund for·last minute" nlers is less than the population mean refund for early filers? Select your answer- Clheck My Work (2 remaining) appropriate hypotheses such that rejection of Ho will support the researcher's conbention. 10. Ho : ? is i -select your answer Ha: ? is ( -select your answer b. For a semple of 400 individuals who filed a tax return between April 10 and 15, the sample mean refund was $910. Besed an prior experience a population standard deviation of ?--$1,600 may be assumed. what is the p-value (to 4 decimals)? 13, c. Using ? = 0.05, can you conclude that the population mean refund for 'last minute" filers is less than the population mean refund for early filers? Select your answer- Answer the next three questions using the critical value approach. d. Using ?-0.05, what is the critical value for the test statistic? Enter negative value as negative number State the rejection rule: Reject a0.05 if zis-Select your answer the critical value. Using ? 0.05 can you condude that the population mean refund for last minute n ers is less than the population mean refund for early filers? Select your answer Check My Work (2 remaining)Explanation / Answer
a) H_0: mu = 1080 vs H_a: mu < 1080
b) mu=1080
n=400
xbar=910
sd = 1600
z =(xbar-mu)/(sd/sqrt(n)) = -2.125
p.value=pnorm(q = z,mean = 0,sd = 1,lower.tail = TRUE) = 0.01679
c) yes, there is significant difference.
alpha = 0.05
z.alpha = qnorm(0.05) = -1.645
z = -2.125
hence, z < z.aplha
therefore population mean refund for last minutes fillers is less than the population mean refund for early fillers.
d) at alpha = 0.05
z.alpha = qnorm(0.05) = -1.645
reject alpha=0.05 if z is less z.alpha the critical value.
using alpha = 0.05 , conclude that the population mean refund for last minute fillers is less than the population mean refund for early filers. true or H_a: accepted.
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