est Final Exam ?: 10 pts 15 of 25 (0 complete) V I a hybridzation ex ng peas wit

Question

est Final Exam ?: 10 pts 15 of 25 (0 complete) V I a hybridzation ex ng peas with green pods and yellow pod He crossed peas in such a way that 25% (or 146) of the 584 olspring peas were expected to have yellow pods. Instead of getting 146 psas with yelow pods, he obtained 18 Assume that the a. Find the probability that among the 584 offs b. Find the probability that among the 584 offspring peas, at least 148 have yellow pods c. Which result is useful for determinir rate of 29% is correct. pring peas , exactly 148 have yellow pods ng whether the claimed rate ol 25% s incorrect? (Part (a) or part (t a The probability that exactly 148 have yellow pods is (Round to four decimal places as needed) b. The probability that at least 148 have yellow pods is (Round to four decimal places as needed.) is uselul for determining whether the claimed rate is incorrect d. Is there strong evidence to suggest that the rate of 25% is incorrect? O Yes

Explanation / Answer

here mean =np=584*0.25=146

and std deviaiton =sqrt(np(1-p))=10.464

a)

P(X=148)=P(147.5<X<148.5)=P((147.5-146)/10.464<Z<(148.5-146)/10.464)=P(0.14<Z<0.24)

=0.5948-0.5557=0.0391 ( please try 0.0392 or 0.0374 if this comes wrong and revert)

b)

P(X>=148)=P(Z>0.14)=0.4443 ( please try 0.4430 if this comes wrong)

c)

part b is useful

d)

No

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