2 of 25 (0 complete) n Hap A sample af colored candies was obtained to the same.

Question

2 of 25 (0 complete) n Hap A sample af colored candies was obtained to the same. If the candy maker wants the dfferent color the weights of different colors. The ANOVA table is shown below It is known that the greatly. Use a 0.025 signilicance level to test the claim that the mean weight of different colared candes s y normal and the variances do not differ popuíations to have the same mean weight, do these results suggest that the compary has a probiem reqaning Test Stat, F: Cntical F P.Value: Source DF MS 0009 2 9889 2.7178 00155 Ermor Total:91 0.045 0 0.258 0003 0.303 Should the nul hypothesis that all the colors have the same mean weight be rejected? O A. Yes, because the P.value is less than the significance level. OB. Yes. O C. No, because the P-value is less than the significance level O D. No, because the P-value is greater than the signficance level s greater Does the company have a problem requring corrective action? OA. No, because it is not likely that the candies do not have equal mean weights. O B. No, because it is likely that the candies do not have equal mean weights ° C. Yes, because it is not likely that the candes do not have equal mean weights D. Yes hecause it is likalv that the candies dy not hawe enial mean weirnhts Click to select your answer 6/3/18 Date Submitted Pearson Tutor Services for

Explanation / Answer

We should reject the null when our p value is smaller than our alpha level. We should not reject the null if our critical f value is smaller than our F Value, unless we also have a small p-value.

Here, alpha level= 0.025 and p value= 0.0155 < 0.025

Hence, we reject the null hypothesis.

Therefore, the correct answer is: (A)

Since the null is rejected, it indicates that all the colored candies do not have equal mean weight. So, the company does not have any problem requiring corrective action.

So, the correct answer is (B)

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