iPad? 7:11 PM 16% 0 6:58:37 Exit c) In the context of this study, describe a Typ
ID: 2907634 • Letter: I
Question
iPad? 7:11 PM 16% 0 6:58:37 Exit c) In the context of this study, describe a Type I error and a Type II error. Choose a File D2 Suppose that the study in problem #2 was performed with a random sample of n-121 patient contacts where a plain ring was worn, and 40 of these patient contacts resulted in bacterial transmission a) Describe the shape, center, and spread of the sampling distribution of p if the mul hypothesis H.: 0.25 were true b) Is there convincing evidence that the null hypothesis is not true, or is p consistent Carry out a with what you would expect to see if the null hypothesis were true? hypothesis test to answer this question. Choose a File 3 One method of human locomotion that appears to have no function except to express joy is skipping, a skill usually leamed in early and middle childhood. Each person in a random sample of female students and a random sample of male students at a large middle school was asked, "Approximately how long ago did you last spontaneouslyExplanation / Answer
Solution2a:
sample szie=n=121
large sample as ni s greater than 30
According to central limit theorem follows normal distribution
mean=p^=p=0.25
standard deviation=sqrt(p^(1-p^)/n=sqrt(.25*(1-0.25)/121)=0.0393
sahpe is normal
Solution2b:
Step1:state null and alternative hypothesis
Null hypothesis:H0:p=0.25
Alternative hypothesis:H1:p not =0.25
Step2:state level of significance
alpha=0.05
Step3:
Test statistic
Z=p^-p/sqrt(p(1-p)/n
p^=x/n=40/121=0.3305785
p=0.25
n=121
z=0.3305785-0.25/sqrt(0.25*(1-0.25)/121)
z=2.047
z=1.959
Step4:
state p value
Using R software:
2*pnorm(2.047,mean=0,sd=1,lower.tail = FALSE)
p=0.04065808
Step5 :
Decsion
here p=0.04065808
p<0.05
Reject Null hypothesis.
Accept alternative hypothesis
Step6:
conclusion:
There is sufficient statistical evidence at 5% level of significance that the null hypothesis ,p=0.25 is not true
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