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iPad? 7:11 PM 16% 0 6:58:37 Exit c) In the context of this study, describe a Typ

ID: 2907634 • Letter: I

Question

iPad? 7:11 PM 16% 0 6:58:37 Exit c) In the context of this study, describe a Type I error and a Type II error. Choose a File D2 Suppose that the study in problem #2 was performed with a random sample of n-121 patient contacts where a plain ring was worn, and 40 of these patient contacts resulted in bacterial transmission a) Describe the shape, center, and spread of the sampling distribution of p if the mul hypothesis H.: 0.25 were true b) Is there convincing evidence that the null hypothesis is not true, or is p consistent Carry out a with what you would expect to see if the null hypothesis were true? hypothesis test to answer this question. Choose a File 3 One method of human locomotion that appears to have no function except to express joy is skipping, a skill usually leamed in early and middle childhood. Each person in a random sample of female students and a random sample of male students at a large middle school was asked, "Approximately how long ago did you last spontaneously

Explanation / Answer

Solution2a:

sample szie=n=121

large sample as ni s greater than 30

According to central limit theorem follows normal distribution

mean=p^=p=0.25

standard deviation=sqrt(p^(1-p^)/n=sqrt(.25*(1-0.25)/121)=0.0393

sahpe is normal

Solution2b:

Step1:state null and alternative hypothesis

Null hypothesis:H0:p=0.25

Alternative hypothesis:H1:p not =0.25

Step2:state level of significance

alpha=0.05

Step3:

Test statistic

Z=p^-p/sqrt(p(1-p)/n

p^=x/n=40/121=0.3305785

p=0.25

n=121

z=0.3305785-0.25/sqrt(0.25*(1-0.25)/121)

z=2.047

z=1.959

Step4:

state p value

Using R software:

2*pnorm(2.047,mean=0,sd=1,lower.tail = FALSE)

p=0.04065808

Step5 :

Decsion

here p=0.04065808

p<0.05

Reject Null hypothesis.

Accept alternative hypothesis

Step6:

conclusion:

There is sufficient statistical evidence at 5% level of significance that the null hypothesis ,p=0.25 is not true