the area that lies between z=-1.31 and z=1.31 is This Question: 1 pt 47 of 10 (6

Question

the area that lies between z=-1.31 and z=1.31 is

This Question: 1 pt 47 of 10 (6 complete) This Test: 10 pts Det mine the area unde' the standard nomnal curve that lies between a z--1 31 and Z e 131 z--? 13 and zs and e z 19 and 2 136 (a) The area that hes between Z-131 and 131 is (Round to four decimal places as needed ) (b) The area that les between z -013 andz-015 (Round to four decimal places as needed (c) The area that ies between Z ?? 19 and Z : 136 is Round to four decimal places as needed) re to search 5 6 8

Explanation / Answer

a) The area here is computed as:

P( -1.31 < Z < 1.31 )
= P(Z < 1.31) - P(Z < -1.31)

Getting it from the standard normal tables, we get:
= 0.9049 - 0.0951
= 0.8098

Therefore 0.8098 is the required area here.

b) The area here is computed as:
P(-0.13 < Z < 0)
= P(Z < 0) - P(Z < -0.13)
= 0.5 - 0.4483
= 0.0517

Therefore 0.0517 is the required area here.

c) The area here is computed as:
P(1.19 < Z < 1.36)
= P(Z < 1.36) - P(Z < 1.19)

Getting it from the standard normal tables, we get:
= 0.9131 - 0.8830
= 0.0301

Therefore 0.0301 is the required area here.

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