emap on the following page (Figure 2) is at a scale of 1:2400 (I\" 200) and show
ID: 290504 • Letter: E
Question
emap on the following page (Figure 2) is at a scale of 1:2400 (I" 200) and shows arn sediol no significant topographic change. The region is composed of a set of mentary beds, shown by the different patterns, which dip uniformly 60° to the dips 70° southwara two fauls present (7 and /2), where /I dips 60° northward and 2 southeast. There are termine the type of fault (normal or reverse, with the appropriate direction for any I. What is the amount and orientation of the net slip II. What are the dip-slip and strike-slip component magnitudes? ateral motion) and the net slip for fault /2. hanging wall and footwall of fault f2. a) De lateral motion) Be sure to show your models of both the III. Classify the fault according to minor-major slip sense of motion. IV. Report the amount and direction of the rake angles used to solve the problem on the stereonet. b) Slickenlines on fault fl show only dip-slip movement has occurred. Determine the type of fault (normal or reverse) and the net slip for faultfl. If these are not possible to determine, explain why the type of fault and net slip on fi cannot be determined. I. What is the amount of strike separation on the f1 fault? II. What is the amount and orientation of the net slip on fl? III. What are the dip-slip and strike-slip component magnitudes? IV. Classify the fault according to minor-major slip sense of motion.Explanation / Answer
a)The fault f2 dips southward so the southern block is the hanging wall which has moved up the tomographic dip. So, f2 is a reverse fault. For slip amount calculations, the scale is given 1.2400(1"=200") but scale is not plotted on the map. Please draw a scale on the map so as to measure the lengths as in picture how can we under the lengths of the lines in inches without a scale to compare.
But , as an approximation the net slip length appears to be 2" i.e, 400 feet.
I. Amount of net slip is 400 feet in a direction N60°W.
II. Dip slip=346.4 feet and strike slip =200feet
III. The fault is mainly reverse fault because the dip slip motion is dominant and the hanging wall has gone up, but there is strike slip movement to , so actually it is an oblique thrust fault.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.