Determine the product of 800.5 times (2 times 10^6) 1.7 times 10^7 1.601 times 1

Question

Determine the product of 800.5 times (2 times 10^6) 1.7 times 10^7 1.601 times 10^7 1.7 times 10^9 1.601 times 10^9 At a given time, Saturn was 9.1 times 10^8 miles from the Sun and Earth was 9.3 times 10^7 miles from the Sun. By what distance is one planet closer to the Sun than the other planet? 2 times 10^1 2 times 10^5 8.17 times 10^7 8.17 times 10^8 The graph shows the temperature, in degrees Fahrenheit, of a liquid for the first ten minutes of a heating experiment. Based on the graph, which expression could be used to calculate the temperature of the liquid after m minutes? 5m + 40 -5m -40 10m +40 -10m -40 What is the value of the expression (-2)^3 (-2)^2 ? -64 -32 32 64

Explanation / Answer

800.5x(2x106) = (800.5x2)x106 = 1601x106 = 1.601x103 x 106 = 1.601x109.Option D is the correct answer. If Saturn is 9.1 x 108 and Earth is 9.3 x 107 miles distant from Sun, then the distance by which one planet is closer to the Sun than the other planet is 9.1 x 108 - 9.3 x 107 miles = 91x107 -           9.3 x 107 = 81.7x107 miles = 8.17x10 x107 miles = 8.17x108 miles. Option D is the correct answer. The initial temperature (time = 0) is 400 F and the temperature after 8 minutes of heating is 800F. Thus, the rate of change of the temperature is (80-40)/(8-0) = 40/8 = 5. Thus, the required expression for temperature after m minutes is 5m +40.Option A is the correct answer. (-2)3(-2)2 = -8x 4 = -32. Option B is the correct answer.

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