%3Cdiv%20style%3D%22margin%3A%26nbsp%3B0px%3B%26nbsp%3Bpadding%3A%26nbsp%3B0px%3
ID: 2900494 • Letter: #
Question
%3Cdiv%20style%3D%22margin%3A%26nbsp%3B0px%3B%26nbsp%3Bpadding%3A%26nbsp%3B0px%3B%26nbsp%3Bborder%3A%26nbsp%3B0px%26nbsp%3BcurrentColor%3B%26nbsp%3Bleft%3A%26nbsp%3B0px%3B%26nbsp%3Btop%3A%26nbsp%3B0px%3B%26nbsp%3Bwidth%3A%26nbsp%3B707px%3B%26nbsp%3Bheight%3A%26nbsp%3B0px%3B%26nbsp%3Bposition%3A%26nbsp%3Babsolute%3B%26nbsp%3Bz-index%3A%26nbsp%3B101%3B%22%3E%3Cdiv%26nbsp%3Bstyle%3D%22height%3A%26nbsp%3B145px%3B%22%26nbsp%3Bid%3D%22MathJax_MSIE_Frame%22%3E%3C%2Fdiv%3E%3C%2Fdiv%3E%3Cfont%26nbsp%3Bface%3D%22CMR12%22%3E%3Cp%3EA%26nbsp%3Bperson%26nbsp%3Bhas%26nbsp%3B20%26nbsp%3Bidentical%26nbsp%3Bcandies%2C%26nbsp%3Band%26nbsp%3Ban%26nbsp%3Bunlimited%26nbsp%3Bsupply%26nbsp%3Bof%26nbsp%3Bidentical%26nbsp%3Bbags.%26nbsp%3BShe%26nbsp%3Bgrabs%26nbsp%3Ba%26nbsp%3Bcertain%26nbsp%3Bnumber%26nbsp%3Bof%26nbsp%3Bbags%26nbsp%3Band%26nbsp%3Bdistributes%26nbsp%3Ball%26nbsp%3Bthe%26nbsp%3Bcandy%26nbsp%3Bamong%26nbsp%3Bthese%26nbsp%3Bbags%26nbsp%3Bso%26nbsp%3Bthat%26nbsp%3Bat%26nbsp%3Bleast%26nbsp%3Bone%26nbsp%3Bcandy%26nbsp%3Bis%26nbsp%3Bin%26nbsp%3Beach%26nbsp%3Bbag.%26nbsp%3BHow%26nbsp%3Bmany%26nbsp%3Bways%26nbsp%3Bcan%26nbsp%3Bthis%26nbsp%3Bbe%26nbsp%3Bdone%3F%26nbsp%3BHow%26nbsp%3Bmany%26nbsp%3Bways%26nbsp%3Bcan%26nbsp%3Bit%26nbsp%3Bbe%26nbsp%3Bdone%26nbsp%3Bif%26nbsp%3Bshe%26nbsp%3Bdoesn't%26nbsp%3Bplace%26nbsp%3Bmore%26nbsp%3Bthan%26nbsp%3B5%26nbsp%3Bcandies%26nbsp%3Bin%26nbsp%3Bany%26nbsp%3Bbag%3F%3C%2Ffont%3E%3C%2Fp%3EExplanation / Answer
now she can use max 20 bag keeping one candy in all of them
and min 1 bag keeping all the candy in one
thus number of ways =1 to 20 bag possible= 20 [ANSWER]
now if maximum 5 candies is limit we have to minimum use 4 bags
and maximum bag used is 20 only keeping 1 in all of them
thus total case = 4 to 20 bags = 17 [ANSWER]
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