The key step is to double the number of sides of the inscribed and circumscribed

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The key step is to double the number of sides of the inscribed and circumscribed polygons - in this ease from n = 4 sides (a square) to n = 8 sides (an octagon). Have a good look at Figure 2, which shows a piece of the circle. Line segments AB and BC are half of two sides of the circumscribed square, so their length is S squareroot 2. Line segment AC is one side of the inscribed square, so its length is t4. Doubling the number of sides, EG is one side of the circumscribed octagon, so its length is AF and CF are sides of the inscribed octagon, so their lengths are t_g. The first task is to relate s_4 and t_4 to s_B and. We do it in steps.

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