The ordering and tranportation cost C for components used in a manufacturing pro

Question

The ordering and tranportation cost C for components used in a manufacturing process is approximated by C(x) = 21 (1/x + x/(x+3)) where C is measured in thousands of dollars and x is the order size in hundreds According to Rolle's Theorem the rate of change of the cost must be 0 for some order size in the interval (3.6) find this order size. Round your answer to three decimal places

I know that the answer is 4.098 but I would like some sort of explanation about the mathmatics....like the steps involved in this

Explanation / Answer

C'(x) = 21(-1/x2 + 3/(x+3)2) = 0

21[-(x+3)2 + 3x2 ]/x2(x+3)2= 0

-(x+3)2 + 3x2 = 0

(3x - (x+3))(3x + (x+3)) = 0

3x - (x+3) = 0 -> (3-1)x = 3 -> x = 3/(3-1) = 4.098

3x + (x+3) = 0 -> (3+1)x = -3 -> x = -3/(3+1) -> out of interval [3,6]

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.