R RI 56% Wed 26 AM a E Chrome File Edit View History Bookmarks People Window Hel

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R RI 56% Wed 26 AM a E Chrome File Edit View History Bookmarks People Window Help AJ Free Online Business Card X Extra Practice C 4. The Light Produced By x isd.net/Te L campus kellerisd.net/Tea t/Teachers/24947/Lists/Calendar/Attachments/532/7-4%20Quadratic%20Word%20Problems%20HW%20PAPpd Apps Book h Hotmail h moodle york: My ho h YouTub h Goog Facebook h Online Banking Sig h Fullcontact h Kijiji City of Toronto Other Bookmarks 5. A player bumps a volleyball with an initial vertical velocity of20 ft/s. a. Write a function h in standard form for the ball's height in feet in terms of the time t in seconds after the ball is hit. (Hint: h(t) 16t vot ho) 2+ ft 4 ft b. What is the maximum height of the ball? c. Suppose the volleyball were hit under the same conditions, but with an initial velocity of 32 fts. How much higher would the ball go?

Explanation / Answer

a) h(t) = 16t2 + vo t + ho

vo = 20ft/s

ho = 4ft

h(t) = -16t2 + 20t + 4

b) maximum height of ball :

dh/dt = -32 t + 20

-32 t + 20 =0

t = 20/32 = 0.625 s

h(0.625) = -16 (0.625) + 20 (0.625) + 4 = 6.5 ft

c) vo = 32ft/s

h(t) = 16t2 + 32 t + 4

dh/dt = -32t + 32

32t +32 =0

t = 1s

h(1) = -16(1)2 + 32 + 4 = -16 + 36 = 20 ft

The ball will go 20 ft higher

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