o 0/1 points I Previous Answers LarCalc10 6.3.076 My Notes Ask Your Teacher Solv
ID: 2895680 • Letter: O
Question
Explanation / Answer
We have given equation (x3+y3)dx-xy2dy=0
(x3+y3)dx=xy2dy
dy/dx =(x3+y3)/(xy2)
dy/dx =(x3)/(xy2)+(y3)/(xy2)
dy/dx =(x2)/(y2)+y/x
substitute y=vx,dy/dx=v+x(dv/dx) and v=y/x
v+x(dv/dx) =(1/v)2+v since x/y=1/v and v=y/x
x(dv/dx) =(1/v)2
(dv/dx) =(1/v2)*(1/x)
separate the variable
v2dv=dx/x
integrating both sides
v3/3=ln(x)+C
v3=3*ln(x)+C
v=[3*ln(x)+C]1/3
substitute back v=y/x
y/x=[3*ln(x)+C]1/3
y=x*[3*ln(x)+C]1/3
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.