An investment of $82,000 was made by a business club. The investment was split i

Question

An investment of $82,000 was made by a business club. The investment was split into three parts and lasted for one year. The first part of the investment earned 8% interest, the second 6%, and the third 9%. Total interest from the investments was $6300. The interest from the first investment was 4 times the interest from the second. Find the amounts of the three parts of the investment. What is the amount of the first part of the investment? $ What is the amount of the second part of the investment? $ What is the amount of the third part of the investment? $

Explanation / Answer

let the first part of investment be x,second part of investment be y,third part of investment be z,

total investment = x+y+z=82000

total interest =0.08x +0.06y +0.09z =6300

=>8x+6y+9z=630000

interset from first investment is four times the interest from second

=>0.08x=4*0.06y

=>x=3y

x+y+z=82000 ,8x+6y+9z=630000 , x=3y

=>3y+y+z=82000 ,8(3y) +6y+9z=630000

=>4y+z=82000 ,30y+9z=630000

=>z=82000-4y ,30y+9z=630000

=>30y+9(82000-4y) =630000

=>30y +738000-36y =630000

=>6y =108000

=>y=18000

x=3y , y=18000

=>x=3*18000

=>x=54000

x+y+z=82000 ,x=54000, y=18000

=>z=82000-54000-18000

=>z=10000

first part of investment is 54000 $ ,second part of investment is 18000 $ ,third part of investment is 10000 $,

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