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Today we will investigate how we may determine the nature of the original functi

ID: 2892825 • Letter: T

Question

Today we will investigate how we may determine the nature of the original function just from knowledge of the rate of change of the function. Recall: An equation of the form dy/dx = some expression is a differential equation if, upon appropriate substitution of the function and/or its derivative(s), the differential equation is true. a) Verity that y = x^3 + C is a solution for the differential equation dy/dx = 3x^2. b) verify further that y = x^3 + 4 is a solution the differential equation dy/dx = 3x^2 with y(0) = 4. Definitions: The statement y(0) = 4 is an initial condition, and the differential equation and the initial condition are together an initial-value problem.

Explanation / Answer

From the given question,

part 1

a) dy/dx= 3x2

dy= 3x2 dx

integrating both sides

y= 3x3/3 +c

y=x3+c

Thus y=x3+c is a solution of differential equation dy/dx= 3x2

b) dy/dx= 3x2, y(0)=4

From the previous answer, y=x3+c

when x=0, y=4

4=03+c

c=4

rewriting the equation,y=x3+4

Hence y=x3+4 is solution of initial value, differential equation dy/dx= 3x2, y(0)=4.

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