This is what I have so far. Please help, I cannot figure out how to find the cri
ID: 2891513 • Letter: T
Question
This is what I have so far. Please help, I cannot figure out how to find the critical points and after that.
Explanation / Answer
4x^3y^2 - 4y = 0
x^3y^2 - y = 0
y(x^3y - 1) = 0
y = 0 , x^3y = 1 ---> equatiom 1
2x^4y - 4x + 3y^2 = 0 ---> equation 2
Now, put y = 0 into eqn 2 :
-4x = 0
x = 0
Now, put x^3y = 1 into equation 2 :
2x - 4x + 3/x^6 = 0
-2x + 3/x^6 = 0
(3 - 2x^7)/x^6 = 0
x = (3/2)^(1/7)
When x = (3/2)^(1/7),
y = 1/x^3, which becomes
y = (2/3)^(3/7)
So, we have :
criticals
(0,0)
((3/2)^(1/7) , (2/3)^(3/7))
Hope this made sense !
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