Question
e | www.webassign.net/web/Student/Assignment-Responses/last?dep-9503714#QS o Apps Bookmarks DM1ife Insider DAAUS Web Loggings DInfor Expense Manag OMGM Resorts-Prod D Konos Senes Cent 5. 0/1 points l Previous Answers scalcET6 105.AE07 EXAMPLE 7 Sketch the conic below and find its foci. 4y 288x 16y 704o We complete the squares as follows: 36x SOLUTION 4(y 4y 2 704 16 576 -36(x - (y Video Example) Tutorial This is in the standard form except that x and y are replaced by x-4 and y-2. Thus a.-16 X , and c- ) and (4, -4.32) and the vertices are (4, The hyperbola is shifted four units to the right and two units upward. The foci are (4, Online Textbook ) and (4, -4). The asymptotes are y 2 (3)x4)- The hyperbola is sketched in the figure. Need Help? Talk to aTutor Submit Answer Save Progress Practice Another Version 6. 1/1 points I Previous Answers SCalcET6 10.5.015 Use the given equation to answer the following questions.
Explanation / Answer
36x2-4y2-288x+16y+704=0
4(y2-4y+4)-36(x2-8x+16)=704+16-576
4(y-2)2-36(x-4)2=144
(y-2)2/36-(x-4)2/4=1
a2=36,b2=4,c2=(a2+b2)= 40
Therefore focii(h,k+-c)= (4,2+-2 sqrt10)=(4, 2-2 sqrt10),(4,2+2sqrt 10)
And vertices =(h,k+-a)=(4,2+-6)=(4,-4),(4,8)
