Interpret the definite integral A = j dA-IL(r) dr as computing the area of a reg

Question

Interpret the definite integral A = j dA-IL(r) dr as computing the area of a region in the xy-plane. Then one can think of the definite integral as: A the antiderivative of L(x). 0 B both "accumulating" all of the small segments of area "da" from a to b AND "accumulating" all of the small segments of area "L(x) dx" froma to b, where L(x) represents the length of a rectangle at a particular x value, and dx the width. o c. "accumulating" all of the small segments of area "L(x)-dr', from a to b, where L(x) represents the length of a rectangle at a particular x value, and dx the width. O D. the antiderivative of dA. O E. "accumulating" all of the small segments of area "dA" from a to b

Explanation / Answer

Dear student.

Answer is (B).

Explanation- As integration is used to find out area of curve where Area =length ×breadth .. and we use integration where L(x) represent length of rectangle at particular value of x and 'dx' represents width of small elements ... (L.dx ) represents small segments of area and if we integrate from 'a' to 'b' it shows total area of curve or rectangle.

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