O Take a Test Hunter Moser x Quizzes & Tests Mathway Math Problem solve x cheggs
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O Take a Test Hunter Moser x Quizzes & Tests Mathway Math Problem solve x cheggsolve the following line e x C Secure https:/www.mathod.com/Student/PlayerTest aspontestid-154320065¢erwinayes; Apps Astronomy (DLogin TN eCampus Luterature class ol Moser, Hunter -ou.. P finite ChargerNet power. MATH 1630 C01 TR 1100 Test: Linear Programming Test 01:13:13 Submit Test This Question: 1 pt This Test: 13 pts possib 8 of 13 (12 complete) EQuestion Help Abicycle manufacturer buids one, three and ten The both aluminum and steel. The company has avalable 32.115 units of steeland s.37s units aluminum. The one-, three-, and ton-speed models need, respeotively, 9, 12 and 15 units of steel and 20, 15, and 25 units of aluminum. How many of each type of boyoleshould be made in order to maximize profit if the company makes $3 per one speed bike, $4 per three speed, and $10 per ten-speed. what is the maximum possible profit? Type the number of each type of boyde that should be made. one speed The maximum proft is Enter your answer in each of the answer boxes.Explanation / Answer
Let no of one cycle models be x, two cycle models y and three cycle models z.
Then profit = z= 3x+4y+10z
Our objective is to maximize z
Constraints are:
Steel to be used = 9x+12y+15z <=32115 and
20x+15y+25z <=54375
First let us solve for equality
3x+4y+5z = 10705 (by dividing first equation by 3)
4x+3y+5z = 10875 ( by dividing ii equation by 5)
x-y = 170.
x=y+170 substitute this in 3x+4y+5z = 10705
3y+510+4y + 5z = 10705 or 7y+5z = 10195
i.e. (y,z intercepts)= (1456, 2039)
Hence optimal solutions are (0,1456,0) Or (0,0,2039) Or (170,0, 0)
Z for (0,1456,0) = 5824
Z for (0,0,2039) = 20390 maximum profit
one model = 0
Two model = 0
Three model = 2039 gives maximum profit of 20390
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