22. Record the amount of incoming solar radiation at an 26 initial setting witho

Question

22. Record the amount of incoming solar radiation at an 26 initial setting without cloud cover Date: June 22 Time: Latitude: 30N Albedo: 15% Clouds Incoming SW radiation 12:00 High: 0 Medium: 0 Low: 0 23. Compare this value with 1352Wm2 (the amount of solar radiation at the top of the atmosphere at 30° N on June 22). What do you think accounts for the reduction in solar radiation striking Earth's surface? 27 24. Add some combination of cloud s to reduce incoming solar radiation by approximately half. Record your results Date: Time: Latitude: 30° N Albedo: 1s% Clouds: High: June 22 12:00 28 Medium: Low: Incoming SW radiation:

Explanation / Answer

22. Ans:

Date given is 22 june It is Summer Solstics

time - 12:00

Latitude = 30 Degree North

Albedo - ( it is defined as the proportion of light that is being reflected back into the space due the presence of cloud or stratosphere layer. ) = 15%

solar insolation I = S cos Z

where s = 1000 W/s2 (clear sky solar radiation sun rays fall perpendicular)

Z = solar zenith angle which 6.5 degree on 22 june (because zenith angle = latitude- sun declination = 30- 23.5 = 6.5)

so solar radiation = 6500 W/m2

albedo is 15% means 15% of incoming solar radiation is return back to space =975 w/m2

So Net solar insolation (after albedo) is that region will be 6500-975 = 5525 W/m2

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