The given region is the combination of a semicircle with radius 2 cm and a right

Question

The given region is the combination of a semicircle with radius 2 cm and a right isosceles triangle with base length 4 km. Find the area of the given region using the formula for the area of a circle, A = pi r^2 where r is the circle's radius, and the formula for the area of a triangle, A = bh/2 where b and h are the lengths of the triangle's base and height, respectively. Remember, a semicircle's area is one half the area of the circle with the same radius. None of these 8 + 2 pi cm^2 8 + 4 pi cm^2 16 + 4 pi cm^2 16 + 2 pi cm^2

Explanation / Answer

here the above region is made of two segments.

one semi circle on left and traingle on the right

area of semicirle =pi*r2 /2 = pi*22/2 =2pi

and area of traingle =(1/2)*base*height =(1/2)*4*4 =8

hence total are of region =8+2*pi

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