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using the integers from 1 to 30, inclusive, all possible products of six consecu

ID: 2879377 • Letter: U

Question

using the integers from 1 to 30, inclusive, all possible products of six consecutive integers are calculated . How many of the products end in exactly two zeros? Can you please show the algebraic way to solve it? using the integers from 1 to 30, inclusive, all possible products of six consecutive integers are calculated . How many of the products end in exactly two zeros? Can you please show the algebraic way to solve it? using the integers from 1 to 30, inclusive, all possible products of six consecutive integers are calculated . How many of the products end in exactly two zeros? Can you please show the algebraic way to solve it? using the integers from 1 to 30, inclusive, all possible products of six consecutive integers are calculated . How many of the products end in exactly two zeros? Can you please show the algebraic way to solve it?

Explanation / Answer

we have given integers 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30.

we find the product of six consecutive integers.

1*2*3*4*5*6=720

2*3*4*5*6*7=5040

3*4*5*6*7*8=20160

4*5*6*7*8*9=60480

5*6*7*8*9*10=151200

6*7*8*9*10*11=332640

7*8*9*10*11*12=665280

8*9*10*11*12*13=1235520

9*10*11*12*13*14=2162160

10*11*12*13*14*15=3603600

11*12*13*14*15*16=5765760

12*13*14*15*16*17=8910720

13*14*15*16*17*18=13366080

14*15*16*17*18*19=19535040

15*16*17*18*19*20=27907200

16*17*18*19*20*21=39070080

17*18*19*20*21*22=53721360

18*19*20*21*22*23=72681840

19*20*21*22*23*24=96909120

20*21*22*23*24*25=127512000

21*22*23*24*25*26=165765600

22*23*24*25*26*27=213127200

23*24*25*26*27*28=271252800

24*25*26*27*28*29=342014400

25*26*27*28*29*30=427518000

The Seven (7) products end in exactly two zeros as below

5*6*7*8*9*10=151200

10*11*12*13*14*15=3603600

15*16*17*18*19*20=27907200

21*22*23*24*25*26=165765600

22*23*24*25*26*27=213127200

23*24*25*26*27*28=271252800

24*25*26*27*28*29=342014400