The velocity of a particle moving along a lines is given by upsilon(t) = t^3 - 2

Question

The velocity of a particle moving along a lines is given by upsilon(t) = t^3 - 2t^2 meter per second. Find the displacement of the particle during the time interval between -2 and 3 seconds. Displacement = (Include the correct units.) To find the total distance traveled by the particle during the time interval from -2 to 3 seconds, we must split the integral of the absolute value of velocity into a sum of two integrals Total distance traveled = integral_-2^3 |t^3 - 2t^2| dt = integral_-2^k upsilon_1 (t) dt + integral_k^3 upsilon_2 (t) dt where upsilon_1 (t) and upsilon_2 (t) are functions and k is a number such that upsilon_1 (t) = (Absolute values are not allowed.) upsilon_2 (t) = (Absolute values are not allowed.) k = Total distance traveled = (Include the correct units.)

Explanation / Answer

According to the question the time varies from t=-2 second to t=3 seconds,

here just notice that time can not be negative.So the question is not correct or can not be solved.

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