A company runs food service concessions for sporting events throughout the count
ID: 2869732 • Letter: A
Question
A company runs food service concessions for sporting events throughout the country. Their marketing research department chose a particular football stadium to test market a new jumbo hot dog. It was found that the demand for the new hot dog is given approximately by
p= 7 - ln(x) when 5<x<500
where x is the number of hot dogs (in thousands) that can be sold during one game at a price of p dollars. If the company pays 1 dollar for each hot dog, how should the hot dogs be priced to maximize the profit per game?
Explanation / Answer
p = 7 - ln(x) when 5 < x < 500
Total number of dogs sold = x thousand
So, total revenue = x * p
R = x(7 - ln(x))
R = 7x - xln(x)
Company pays 1 dollar per dog
So, total cost , C = 1 * x = x
Profit = R - C
P = 7x - xln(x) - x
P = 6x - xln(x)
Deriving :
dP/dx = 6 - d/dx(xln(x))
dP/dx = 6 - x*d/dx(ln(x)) - ln(x)*d/dx(x)
dP/dx = 6 - x(1/x) - ln(x)
dP/dx = 5 - ln(x)
Since this must be maximized, dP/dx = 0
5 - ln(x) = 0
ln(x) = 5
x = e^5
Now, p = 7 - ln(x)
Plug in the value of x :
p = 7 - ln(e^5)
p = 7 - 5
p = 2
So, each dog must be priced at $2 to maximize profit ----> ANSWER
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