A study suggests that the extinction rate r(t) of marine animal families during
ID: 2861536 • Letter: A
Question
A study suggests that the extinction rate r(t) of marine animal families during the Phanerozoic Eon can be modeled by the function r(t) = 3130/(t + 262) for 0 t 544, where t is time elapsed (in millions of years) since the beginning of the eon 544 million years ago. Thus, t = 544 refers to the present time, t = 540 is 4 million years ago, and so on. Compute the average of Rn and Ln with N = 10 to estimate the total number of families that became extinct in the periods 80 t 280. (Round your answer to three decimal places.)
Explanation / Answer
N=10
t =(280-80)/10 =20
Rn=20[ 3130/(90 + 262)+ 3130/(100 + 262)+ 3130/(110 + 262)+ 3130/(120 + 262)+ 3130/(130 + 262)+ 3130/(140 + 262)+ 3130/(150 + 262)+ 3130/(160 + 262)+ 3130/(170 + 262)+ 3130/(180 + 262)+ 3130/(190 + 262)+ 3130/(200 + 262)+ 3130/(210 + 262)+ 3130/(220 + 262)+ 3130/(230 + 262)+ 3130/(240 + 262)+ 3130/(250 + 262)+ 3130/(260 + 262)+ 3130/(270 + 262)+ 3130/(280 + 262)]
Rn=62600[ 1/(90 + 262)+ 1/(100 + 262)+ 1/(110 + 262)+ 1/(120 + 262)+ 1/(130 + 262)+ 1/(140 + 262)+ 1/(150 + 262)+ 1/(160 + 262)+ 1/(170 + 262)+ 1/(180 + 262)+ 1/(190 + 262)+ 1/(200 + 262)+ 1/(210 + 262)+ 1/(220 + 262)+ 1/(230 + 262)+ 1/(240 + 262)+ 1/(250 + 262)+ 1/(260 + 262)+ 1/(270 + 262)+ 1/(280 + 262)]
=2852.950559
Ln=62600[ 1/(80 + 262)+ 1/(90 + 262)+ 1/(100 + 262)+ 1/(110 + 262)+ 1/(120 + 262)+ 1/(130 + 262)+ 1/(140 + 262)+ 1/(150 + 262)+ 1/(160 + 262)+ 1/(170 + 262)+ 1/(180 + 262)+ 1/(190 + 262)+ 1/(200 + 262)+ 1/(210 + 262)+ 1/(220 + 262)+ 1/(230 + 262)+ 1/(240 + 262)+ 1/(250 + 262)+ 1/(260 + 262)+ 1/(270 + 262) ]
=2916.489739
average =[2852.950559+2916.489739]/2
average=2884.720
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