Pretend down syndrome is a recessive trait and is represented by ss. 80% of affe
ID: 28604 • Letter: P
Question
Pretend down syndrome is a recessive trait and is represented by ss. 80% of affected ss people cannot have children. However, As and AA people are not affected. (AA being homozygous dominant for no trait, As being Heterozygous for trait)
Based off of 10,000 people,
AA = 7561
As = 2416
ss = 23 (With down syndrome)
a) What are the genotype, allele, and the phenotype frequencies?
b) Is this population in HWE (Hardy-Weinberg Equilibrium?) Please include work and reason why, I actually need to learn this for my test coming up.
Also, please use the chi-square distribution
Explanation / Answer
Pretend down syndrome is a recessive trait and is represented by ss. 80% of affected ss people cannot have children. However, As and AA people are not affected. (AA being homozygous dominant for no trait, As being Heterozygous for trait)
Based off of 10,000 people,
AA = 7561
As = 2416
ss = 23 (With down syndrome)
a) What are the genotype, allele, and the phenotype frequencies?
b) Is this population in HWE (Hardy-Weinberg Equilibrium?) Please include work and reason why, I actually need to learn this for my test coming up.
Also, please use
P^2+2pq+q^2=1
q^2=23/10000
q= square root of 0.0023=0.047
p+q=1
p=1-0.047=0.953
genotype
Observed
Expected
O-E
(O-E)^2/E
AA
P^2
7561
0.953 x0.953 x10000=9082
305
As
2pq
2416
2x0.953x 0.047 x10000=896
ss
23
0.047 x0.047x10000=2209
q^2
10000
CHISQUARE =(O-E)^2/E
CALCUALTED VALUE IS MORE THAN TABLE VALUE
HENCE THE POPULAYION IS NOT IN HARDY WEIBNERG EQUILIBRIUM
genotype
Observed
Expected
O-E
(O-E)^2/E
AA
P^2
7561
0.953 x0.953 x10000=9082
305
As
2pq
2416
2x0.953x 0.047 x10000=896
ss
23
0.047 x0.047x10000=2209
q^2
10000
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